Question

A charge of `3 C` is at `(3, -1 )` and a charge of `-2 C` is at `( -3, 7 )`. If both coordinates are in meters, what is the force between the charges?

Answer 1

`F~=-0,372.10^9N`

Explanation:

`step-1:"find distance between the point of(3,-1) and (-3,7)"`
`"distance between two point can be find:" r^2=Delta x^2+ Delta y^2`
`r^2=(3+3)^2+(-1-7)^2`
`r^2=9^2+(-8)^2=81+64=145`
`step-2:"use Coulomb's law"`
`F=(k*q_1*q_2)/r^2`
`F=(9.10^9*3*(-2))/145`
`F=(-54*10^9)/145`
`F~=-0,372.10^9N`