A charge of 3 C is at (3, -1 ) and a charge of -2 C is at ( -3, 7 ). If both coordinates are in meters, what is the force between the charges?

1 Answer
Feb 18, 2016

F~=-0,372.10^9N

Explanation:

step-1:"find distance between the point of(3,-1) and (-3,7)"
"distance between two point can be find:" r^2=Delta x^2+ Delta y^2
r^2=(3+3)^2+(-1-7)^2
r^2=9^2+(-8)^2=81+64=145
step-2:"use Coulomb's law"
F=(k*q_1*q_2)/r^2
F=(9.10^9*3*(-2))/145
F=(-54*10^9)/145
F~=-0,372.10^9N