Question

What is the antiderivative of `int (1/y^3 - 2/sqrty )dy`?

Answer 1

`-1/(2y^2)-4sqrt(y)+C`

Explanation:

We can re write this as:

`inty^-3-2y^(-1/2)dy`

Now we can integrate by increasing the power by one and dividing by the new power as usual:

`=y^-2/-2-4y^(1/2)+C`

Re writing this back into a more familiar form gives us:

`= -1/(2y^2)-4sqrt(y)+C`