Question

What is the standard form of `f(x)=(x-1)(x-9)-(2x-1)^2`?

Answer 1

Standard form is `f(x)=−3x^2−6x+8`

Explanation:

To find the standard form of `f(x)=(x−1)(x−9)−(2x−1)^2`, we first simplify this

`f(x)=(x−1)(x−9)−(2x−1)^2`

= `(x−1)x−(x−1)9−((2x)^2−2*2x*1+1^2)`

= `(x^2−x−9x+9)−(4x^2−4x*1+1)`, now grouping them

= `(x^2−4x^2−10x+4x+9-1)`

= `−3x^2−6x+8`