What is int x^2-sqrt(2x)dx?
1 Answer
Feb 21, 2016
Explanation:
The standard integral is
intax^n dx = (ax^(n+1))/(n+1) + c " where c is constant of integration" rewrite
sqrt(2x) = sqrt2 .x^(1/2) and apply the standard integral 'term by term'
rArr int(x^2 - sqrt(2x))dx= x^3/3 - (sqrt2 x^(3/2))/(3/2) + c
= 1/3 x^3 - (2sqrt2)/3 x^(3/2) + c