Question

What is the distance between `(6 , (5 pi)/8 )` and `(3 , (4 pi )/3 )`?

Answer 1

Use the Polar coordinate form of the distance formula which is :

`d^2 = r_1^2 + r_2^2 - (2 xxr_1 xx r_2 xx cos (theta_2 - theta_1 ))`

In this question let `(r_1 , theta_1 ) = (6 , (5pi)/8 )` and

`( r_2 , theta_ 2) = (3 , (4pi)/3 )`

just substitute the values into formula.