Question

How do you normalize `(3i + 2j - 6k)`?

Answer 1

To normalize a vector you just divide each axis modulus with its norm hence

`u_(norm)=u/absu`

where `u=(3,2,-6)` and `absu=sqrt(3^2+2^2+(-6)^2)=7`

so the normal vector is

`u_(norm)=(3/7,2/7,-6/7)`