How much power is produced if a voltage of #6 V# is applied to a circuit with a resistance of #60 Omega#?

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Answer 1 · 2016-02-22T12:20:21

Power #=600mW#

Things you need to know:

#P=IV# (Power equals current times voltage)

#I=V/R# (Current equals voltage divided by resistance

#1" Ampere" = (1 " Volt")/(1 "Ohm")#

#1 " Watt" = 1 " Ampere" * 1" Volt"#

#1 " miliWatt (mW)" = 1" Watt"#

Application

#I= (6" V")/(60 Omega) = 0.1 " A"#

#P= 0.1" A"xx6" V"= 0.6 " W" = 600" mW"#