Question

An object with a mass of `8 kg` is traveling in a circular path of a radius of `12 m`. If the object's angular velocity changes from `5 Hz` to `4 Hz` in `5 s`, what torque was applied to the object?

Answer 1

`L=230,4 N*m`

Explanation:

`L=alpha*I`
`L:" Torque"`
`alpha:" angular acceleration"`
`I:" moment of inertia of object"`
`alpha=(Delta w)/(Delta t)`
`alpha=(2*pi(4-5))/5`
`alpha=-(2*pi)/5`
`I=m*r^2`
`I=8*12^2=144*8=1152`
`L=-(1152*2*pi)/5`
`L=230,4 N*m`