Question

How do you simplify `sqrt128`?

Answer 1

I found: `8sqrt(2)`

Explanation:

I would try by writing `128` in a different way:

`128=4*4*4*2`

so our root becomes:

`sqrt(4*4*4*2)=sqrt(4)*sqrt(4)*sqrt(4)*sqrt(2)`

we know that `sqrt(4)=2`, so:

`sqrt(128)=2*2*2*sqrt(2)=8sqrt(2)`