Question

If the length of a `37 cm` spring increases to `77 cm` when a `3 kg` weight is hanging from it, what is the spring's constant?

Answer 1

`73.5N//m`

Explanation:

From Hooke's Law, `F=kx`

`therefore k=F/x`

`=(3xx9.8)/(0.77-0.37)`

`=73.5N//m`.