Question

How do you factor `12x^3+8x^2 -x-1=0`?

Answer 1

It is `(2x+1)^2*(3x-1)=0`

Explanation:

Rewrite this as follows

#12x^3+8x^2 -x-1=0=>12x^3+12x^2-4x^2-4x+3x-1=0=> (4x^2+4x+1)*3x-(4x^2+4x+1)=0=> (4x^2+4x+1)*(3x-1)=0=> (2x+1)^2*(3x-1)=0#