How do you differentiate #(-x^2 -5x-4 )/ (sinx)# using the quotient rule?
1 Answer
Feb 24, 2016
the answer will be [(-2x-5)sinx-(-x^2-5x-4)cosx]/sin^2x
the answer will be [(-2x-5)sinx-(-x^2-5x-4)cosx]/sin^2x