Question

A gas has a volume of 2.00 L at 323 K and 3.00 atm. What will be the new volume if the temperature is changed to 273 K and the pressure is changed to 1 atm?

Answer 1

We use the combined gas law: `(P_1V_1)/T_1 =(P_2V_2)/T_2`. The volume should reasonably REDUCE on compression and cooling.

Explanation:

So `V_2 =(P_1V_1T_2)/(P_2T_1)` `=` `(1.00*cancel(atm)xx2.00*L*273*cancelK)/(3.00*cancel(atm)xx323*cancelK)` `=` `??L`.