How do you simplify #(3 1/2 + 16 1/2) / (1/3 - 2 1/3)#? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Alan P. · Mir Tareq Feb 26, 2016 -10 Explanation: #(3 1/2 + 16 1/2)/(1/3-2 1/3)# #color(white)("XXX")=(7/2+33/2)/(1/3-7/3)# #color(white)("XXX") = {(7+33)/2}/{(1-7)/3}# #color(white)("XXX")= (40/2)/(-6/3)# #color(white)("XXX") = 20/(-2)# #color(white)("XXX") = -10# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1745 views around the world You can reuse this answer Creative Commons License