How do you solve #4 + 5(3 - x) = 4(8 + 2x)#?

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Answer 1 · 2016-02-26T18:28:47

#x = -1#

#4 + 5(3 − x) = 4(8 + 2x)#

Distribute #5# and #4# to make the equation in its expanded form

#4 + 15 - 5x = 32 + 8x#

Joining common factors or alike integers for each side:

#13x = -13#

Simplify by dividing both sides with #13#

#x = -1#