How do you simplify: #(2asqrt(2))(5asqrt(12))#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Wayne Feb 26, 2016 #20a^2sqrt6# Explanation: #(2asqrt2)(5asqrt12)# #(2a)(5a)(sqrt2)(sqrt12)# #10a^2sqrt24# #(10a^2)sqrt 4sqrt6# #(10a^2)(2)sqrt6# #20a^2sqrt6# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1191 views around the world You can reuse this answer Creative Commons License