A container with a volume of #8 L# contains a gas with a temperature of #270^o C#. If the temperature of the gas changes to #340 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-02-26T22:10:35

#V_2~=5,01 L#

#V_1/T_1=V_2/T_2#
#"convert " ^o C" to " ^o K#
#8/(270+273)=V_2/340#
#8/543=V_2/340#
#V_2=(340*8)/543#
#V_2~=5,01 L#