Question

How do you factor `9y^2(8b-c)-2x^2(c -8b)`?

Answer 1

`(8b - c)(9y^2 + 2x^2)`

Explanation:

Take out -1 as a common factor in the bracket (c - 8b ). This will make it in the same form as (8b - c ) and then use as common factor.

hence `- 2x^2(-1)(8b - c )`

then `9y^2(8b - c ) + 2x^2(8b - c ) = (8b - c )(9y^2 + 2x^2 )`