Question

How do you divide `( -3x^3+ x^2-x-72 )/(x - 2 )`?

Answer 1

`(-3x^3+x^2-x-72)/(x-2)`
`=(-3x^2(x-2)-6x^2+x^2-x-72)/(x-2)`
`=(-3x^2(x-2)-5x(x-2)-10x-x-72)/(x-2)`
`=(-3x^2(x-2)-5x(x-2)-11(x-2)-22-72)/(x-2)`
`=-3x^2-5x-11-94/(x-2)`