How do you solve #log_10 x=-1#?

1 Answer
sente
Feb 27, 2016

Take #10# to the power of each side of the equation to find that

#x=1/10#

Explanation:

By their definition, logarithms have the property that #a^(log_a(x))=x#

Using that, we have

#log_10(x) = -1#

#=>10^(log_10(x)) = 10^(-1)#

#=>x=10^(-1)=1/10#

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