Question

Question #a2dcd

Answer 1

If: `log_y(x) = 1` => then: `x=y`
but if: `log_y(1)=x` => then: `x=0`

Explanation:

Definition of logarithm:
For `x>0`
if: `log_a(x)=y`
then: `x=a^y`

For `x<=0` :
`log_a(x)` is "Undefined"

Answer 2

`x=10`
(what you "knew" was incorrect)

Explanation:

Two points:
[1]`color(white)("XXX")` the default base for `log` is `10`: `log x` means `log_10 x`
[2]`color(white)("XXX")log_b a = k hArr b^k=a`

From [1]
`color(white)("XXX")log x =1` is the same as `log_10 x = 1`

From [2]
`color(white)("XXX")log_10 x = 1 hArr 10^1 = x`

Therefore
`color(white)("XXX")x=10^1 = 10`