If #f(x) = 4x^2 + 3x+7# and #g(x) = 3x-5#, what is #(g@f)(x)#?

1 Answer
Feb 27, 2016

#12x^2 + 9x + 16#

Explanation:

What this means is substitute x # = 4x^2 + 3x + 7 " for x in g(x)"#

Another way of writing (g ○ f)(x) is g(f(x))

#g(f(x)) = g( 4x^2+3x+7) = 3(4x^2+3x+7) - 5 #

#rArr(g○f)(x) = 12x^2 +9x+21 - 5 = 12x^2 + 9x + 16 #