How do you find the derivative of #y = (2x+3)^4 / x#?

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Answer 1 · 2016-02-28T19:03:52

#[(2x+3)^3 (8x^2 -2x-3)]/x^2#

By applying the quotient rule, the derivative would be

#[4(2x+3)^3 (2x)(x) - (2x+3)^4]/x^2#

=#[(2x+3)^3 (8x^2 -2x-3)]/x^2#

Answer 2 · 2016-02-28T20:24:27

#([8x * (2x+3)^3] - [(2x+3)^4]) / x^2#

#d/dx (2x+3)^4/x = ([8x * (2x+3)^3] - [(2x+3)^4]) / x^2#