What are the mean and standard deviation of a binomial probability distribution with #n=114 # and #p=3/49 #?

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Answer 1 · 2016-02-29T05:53:42

Mean #=6 48/49#
S D #=2.56#

Given -

#n=114#
#p=3/49#

#q=1-p=1-3/49=46/49#

Mean

#barx=np=114 xx 3/49=6 48/49#

Variance

#sigma^2=npq=114 xx 3/49 xx 46/49=6.55#

Standard Deviation

#sigma = sqrt(Variance)=sqrt (6.55)=2.56#