How do you write the first five terms of the sequence #3n^2+4# using the nth term rule?
1 Answer
Feb 29, 2016
7 , 16 , 31 , 52 , 79
Explanation:
#3n^2 + 4 " is the nth term rule "# To generate the terms in the sequence , substitute in appropriate values for n and evaluate.
Here use n = 1,2,3,4,5 .
#n = 1 : 3(1)^2 + 4 = 3 + 4 = 7 #
# n = 2 : 3(2)^2 + 4 = 12 + 4 = 16 #
# n = 3 : 3(3)^2 + 4 = 27 + 4 = 31 # I'm sure you can manage the last 2 yourself.