How do you simplify #(6x^4y^8)^3#?

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Answer 1 · 2016-02-29T17:32:07

#216 x^12 y^24#

#(6x^4y^8)^3#

Applying exponential rule, #(a\cdot b)^n=a^nb^n#

#=6^3(x^4)^3(y^8)^3#

#(# #(x^4)^3=x^12 and (x^8)^3 =x^24# by applying exponent rule: #(a^b)^c=a^{b\cdot \c}# #)#

#=6^3x^{12}y^{24}#

( #6^3=216#)

#=216x^{12}y^{24}#