What is the vertex form of a parabola given vertex (41,71) & zeros (0,0) (82,0)?

1 Answer
Mar 1, 2016

The vertex form would be -71/1681(x-41)^2+71

Explanation:

The equation for vertex form is given by:
f(x) = a(x-h)^2 + k , where the vertex is located at point (h,k)

So,substituting the vertex (41,71) at (0,0),we get,

f(x) = a(x-h)^2 + k

0=a(0-41)^2+71

0 = a(-41)^2 + 71

0 = 1681a + 71

a = -71/1681

So the vertex form would be
f(x) = -71/1681(x-41)^2+71.