How do you find two consecutive odd integers such that 3 times the first integer is 5 more than twice the second?

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Answer 1 · 2016-03-01T18:06:35

The consecutive odd integers are #9# and #11#

Let the two consecutive odd integers #= x# and #x+2#

Three times first integer #= 3x#

Five more than twice second#=5 + 2(x+2)#

As per data provided :
#3x = 5 + 2(x+2)#

#3x = 5 + 2(x) + 2 (2)#

#3x = 5 + 2x + 4#

#3x = 2x +9#

#3x -2x = 9#

#x=9#
The next odd integer #= 9+2 = 11#

The consecutive odd integers are #9# and #11#