How do you simplify #(1+2/3)/(3/4-1/3)#?

1 Answer
Mar 1, 2016

You work out the two parts separately into single proper fractions first.

Explanation:

Top: #1+2/3=3/3+2/3=(3+2)/3=5/3#

Bottom: #3/4-1/3=(3/3xx3/4)-(4/4xx1/3)=#
#9/12-4/12=5/12#

So now we're left with #(5/3)div(5/12)#

Division by a fraction can be done by multiplying with the fraction turned 'upside down':
#=(5/3)xx(12/5)=cancel5/cancel3xx(cancel3xx4)/cancel5=4#