Question

How do you find the derivative of `sinh^79(x)`?

Answer 1

`79sinh^78(x)cosh(x)`

Explanation:

According to the chain rule,

`d/dx(u^79)=79u^78*u'`

So:

`d/dx(sinh^79(x))=79sinh^78(x)*d/dx(sinh(x))`

`=79sinh^78(x)cosh(x)`