How do you find the limit of #(e^x + x)^(1/X)# as x approaches infinity?

1 Answer
Mar 2, 2016

#e#

Explanation:

As #x# gets very big the exponential term will completely dominate the linear term, so with that in mind we can conclude that as #x# gets very big the expression becomes:

#(e^x+x)^(1/x)->(e^x)^(1/x)# as #x->oo#

#(e^x)^(1/x)=e^(x/x)=e^1=e#

So the limit is #e#.

If we look at the graph we can see an asymptote at #e# as we would expect:

graph{(e^x+x)^(1/x) [-2.87, 17.13, -1.78, 8.22]}