How do you simplify #e^(1 + ln x)#?
1 Answer
Mar 3, 2016
Explanation:
Use the rule to split up the exponent:
#a^(b+c)=a^b(a^c)#
Thus:
#e^(1+lnx)=e^1(e^lnx)#
Here:
#e^1=e#
#e^lnx=x#
So:
#e^(1+lnx)=e*x#