Question

How do you solve `log x=3/2 log 9+log 2`?

Answer 1

x = 54

Explanation:

using the following`color(blue)" laws of logarithms "`

• logx + logy = logxy

• log`x^n hArr nlogx`

and if `log_bx = log_by rArr x = y`

#rArr logx = log9^(3/2) + log2

[now `[9^(3/2) = (sqrt9)^3 = 3^3 = 27 ]`

`rArr logx = log(27xx2) = log54 rArr x = 54`