Question

If a projectile is shot at an angle of `(pi)/8` and at a velocity of `95 m/s`, when will it reach its maximum height?

Answer 1

`t~=3,71" " s`

Explanation:

`t=v_i*sin alpha/g " elapsed time to maximum height:"`
`t=(95*sin 22,5)/(9,81)`
`t~=3,71" " s`