What is the kinetic energy of an object with a mass of #3 kg# that has been in freefall for #14 s#?

1 Answer
Mar 6, 2016

#=28235.76 J#

Explanation:

if the velocity gained after 14s free fall be v starting with an initial velocity u =0, falling with acceleration g = 9.8#ms^-2#
then
#v=u+g*t=0+9.8*14= 137.2ms^-1#
Hence KE =#1/2mv^2=1/2*3*(137.2)^2=28235.76 J#