Question

How would you describe the graph of `y = 5 * 2^x`?

Answer 1

Use semi-log paper for plotting Y = log y instead of y against x.
The graph is the straight line Y = (log 2) x + log 5.

Explanation:

y is function of the form `ba^x`.
Semi-log graph is good for revealing such relationship for experimental data [(x, y)] through plots in the proximity of a straight line.
Here, taking logarithms,
Y = log y = log 5 + x log 2.= m x + c.
Slope `(dY)/dx` is log 2 and Y-intercept is 5 on the log scale.
Graduations will show 1 unit Y = log 10. So, log 2 = 0.3019 unit of Y.