What is the equation of a circle with center (-3, -5) and radius 4?

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Answer 1 · 2016-03-07T18:13:27

#(x+3)^2+(y+5)^2=16#

A general circle with centre #(a,b)# and radius #r# has equation #(x-a)^2+(y-b)^2=r^2#.

So in this particular case the equation is

#(x+3)^2+(y+5)^2=16#

Answer 2 · 2016-03-07T18:18:00

#x^2+y^2+6x+10y+9=0#

#(x-a)^2+(y-b)^2=r^2#
#a=-3" "b=-5" "r=4#
#(x+3)^2+(y+5)^2=4^2#
#(x+3)^2+(y+5)^2=16#
#x^2+6x+9+y^2+10y+25=16#
#x^2+y^2+6x+10y+9=0#