How do you solve #4x-4y=-16# and #x-2y=-12# using substitution?

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Answer 1 · 2016-03-08T05:57:01

#x=4#
#y=8#

Given -

#4x-4y=-16# ----------------------(1)
#x-2y=-12#-------------------------(2)

Solve equation (2) for ##

#x-2y=-12#
#x=-12+2y#

Substitute >#x=-12+2y# in equation (1)

#4(-12+2y)-4y=-16#
#-48+8y-4y=-16#
#4y=-16+48=32#
#y=32/4=8#
#y=8#

Substitute #y=8# in equation (2)

#x-2(8)=-12#
#x-16=-12#
#x=-12+16=4#
#x=4#