How do you express (x^2 + 33)/(x^3 + x^2)x2+33x3+x2 in partial fractions?

1 Answer
Mar 8, 2016

(x^2+33)/(x^2(x+1)) = -33/x +33/x^2 +34/(x+1)x2+33x2(x+1)=33x+33x2+34x+1

Explanation:

(x^2+33)/(x^2(x+1)) = A/x +B/x^2 +C/(x+1)x2+33x2(x+1)=Ax+Bx2+Cx+1

x^2+33 = A(x(x+1))+B(x+1)+Cx^2x2+33=A(x(x+1))+B(x+1)+Cx2

x^2+33 = Ax^2+Ax+Bx+B+Cx^2x2+33=Ax2+Ax+Bx+B+Cx2

1=A+C, 0=A+B, 33=B1=A+C,0=A+B,33=B

A=-33, B=33, C=34A=33,B=33,C=34

(x^2+33)/(x^2(x+1)) = -33/x +33/x^2 +34/(x+1)x2+33x2(x+1)=33x+33x2+34x+1