How do you solve the following system?: # x + 3-2y=7 , y=2x+9 #

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Answer 1 · 2016-03-09T13:53:03

#(x,y)=(-22/3,-17/3)#

#1)x+3-2y=7#

#2)y=2x+9#

Substitute the value of #y# to the first equation

#rarrx+3-2(2x+9)=7#

#rarrx+3-4x-8=7#

#rarrx+3-4x=7+18#

#rarrx+3-4x=25#

#rarrx-4x=25-3#

#rarrx-4x=22#

#rarr-3x=22#

#rArrx=-22/3#

Now,Substitute the value of #x# to the second equation

#rarry=2(-22/3)+9#

#rarry=-44/3+9#

#rArry=-17/3#