Question

How do you solve `log 8 - (1/3) log x = log 2`?

Answer 1

`x=64`

Explanation:

From the laws of logs we may write this as

`log(8/x^(1/3))=log2`

Now taking the antilog on both sides and cross-multiplying yields

`2x^(1/3)=8`

Now applying laws of exponents and surds and simplifying, we get

`root(3)x=4`

`thereforex=4^3=64`