Question #028d7
1 Answer
Mar 10, 2016
Explanation:
Supposing
with
For
Dividing
f(x-a)/(-(x-a))=((sum_0^n a_i*(x-a)^n))/(-(x-a))
=(a_0+sum_1^n a_i*(x-a)^n)/(-(x-a))
=a_0/(a-x)-sum_1^n a_i*(x-a)^(n-1)=a_0/(a-x)-a_1-a_2*x-...-a_n*x^(n-1)
Soa_0 is the remainder of the division by(a-x) .
But, as we saw above,a_0=f(X=0)
=> alternative(a)