#a+3/(4b)=2# and #b+3/(4a)=6#. How do you find #b/a#?
1 Answer
Mar 10, 2016
Explanation:
If we just examine the first equation:
#(4ab)/(4b)+3/(4b)=2#
#(4ab+3)/(4b)=2#
The second equation, modified similarly, yields:
#(4ab+3)/(4a)=6#
If we take the second equation divided by the first equation, we see that
#((4ab+3)/(4a))/((4ab+3)/(4b))=6/2#
#(4b)/(4a)=3#
#b/a=3#
