Question

How do you convert `(-sqrt2, 3pi/4)` to rectangular form?

Answer 1

`(-sqrt2,(3pi)/4)` in rectangular coordinates is `(1,-1)`

Explanation:

`(r,theta)` in polar coordinates is `(rcostheta,rsintheta)` in rectangular coordinates.

Hence, `(-sqrt2,(3pi)/4)` in rectangular coordinates is

`(-sqrt2xxcos((3pi)/4),-sqrt2xxsin((3pi)/4))` or

`((-sqrt2)xx(-sqrt2/2),(-sqrt2)xxsqrt2/2)` or

`((2/2),-(2/2))` or

`(1,-1)`