What is the derivative of #2^x#?
1 Answer
Mar 11, 2016
Explanation:
#d/dx(e^x) = e^x#
So:
#d/dx(2^x) = d/dx ((e^ln 2)^x)#
#= d/dx(e^(x ln 2))#
#= e^(x ln 2) d/dx (x ln 2)#
#= 2^x ln 2#
