How do you find the definite integral of int (1-2x-3x^2)dx from [0,2]? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer ali ergin Mar 11, 2016 int_0^2(1-2x-3x^2)d x=-10 Explanation: int_0^2(1-2x-3x^2)d x=|x-2*1/2*x^2-3*1/3*x^3|_0^2 int_0^2(1-2x-3x^2)d x=|x-x^2-x^3|_0^2 int_0^2(1-2x-3x^2)d x=2-2^2-2^3 int_0^2(1-2x-3x^2)d x=2-4-8 int_0^2(1-2x-3x^2)d x int_0^2(1-2x-3x^2)d x=-10 Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of ln(7x)? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of x^2-6x+5 from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral 1/(sqrt(49-x^2)) from 0 to 7sqrt(3/2)? How do you integrate f(x)=intsin(e^t)dt between 4 to x^2? How do you determine the indefinite integrals? How do you integrate x^2sqrt(x^(4)+5)? See all questions in Definite and indefinite integrals Impact of this question 3551 views around the world You can reuse this answer Creative Commons License