Question #3b5f1

1 Answer

#11.2g#

Explanation:

ok so first you will find the moles in 16.5g of #Fe_2O_3#
so Moles=mass/molar relative mass
by putting the values #mol=16.5/160# the mols will be #0.1#
so by using the equation we know that 1 mol of #Fe_2O_3# makes
2 mols of #Fe# so by using the ratio method #1:2# and #0.1:x# write these one above the other and cross multiply so the mols of #Fe# we will get will be #0.2# then use the formula moles=mass/molar relative mass #0.2*56=mass# the ans will be #11.2g#