Question

What is the period of `f(t)=sin( ( 11t) /6 )`?

Answer 1

`(12pi)/11`

Explanation:

for the function y = a sin(bx + c)

the amplitude = |a| , period = `(2pi)/b" and c is phase shift "`

here b = `11/6 rArr " period " = (2pi)/(11/6) = (12pi)/11`