How do you solve #4x-3y=-19# and #2x+y=13# using substitution?

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Answer 1 · 2016-03-13T02:00:35

#x=2#
#y=9#

How do you solve 4x−3y=−19 and 2x+y=13 using substitution?

From the given:
Let #4x−3y=−19" "#first equation
Let #2x+y=13" "#second equation

start from second equation

#y=13-2x# insert this equation into the first equation

#4x−3y=−19" "#first equation
#4x−3(13-2x)=−19" "#
#4x-39+6x=-19#
#4x+6x=39-19#
#10x=20#
#x=2#

Solve for y using the second equation

#2x+y=13" "#second equation
#2(2)+y=13" "#
#4+y=13#
#y=13-4#
#y=9#

God bless...I hope the explanation is useful.