What are the solutions of #3x^2 + 14x + 8 = 0#?

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Answer 1 · 2016-03-13T05:01:16

#x=-2/3,-4#

#color(blue)(3x^2+14x+8=0#

This is a Quadratic equation (in form #ax^2+bx+c=0#)

#color(brown)(x=(-b+-sqrt(b^2-4ac))/(2a)#

Where

#color(red)(a=3,b=14,c=8#

Substitute the values in the formula

#rarrx=(-(14)+-sqrt(14^2-4(3)(8)))/(2(3))#

#rarrx=(-14+-sqrt(196-96))/(6)#

#rarrx=(-14+-sqrt100)/(6)#

#rarrcolor(orange)(x=(-14+-10)/(6)#

Now we have #2# values for #x#

#color(indigo)(1))color(green)(x=(-14+10)/6=-4/6=-2/3#

#color(indigo)(2))color(green)(x=(-14-10)/(6)=-24/6=-4#